udd18ql48m的部落格

標題:

想請教大家2條數...(因式分解)

發問:

1) 4x 2次方 - 4xy + y 2次方 - 2x +y 2) 9 - a 2次方 + 3a -ab 註: 唔該連步驟 ．列式清楚

• 求愛麗絲學園鈴聲
• 動物之森問題(有關取CD)
• psp d iso game係點解

 

此文章來自奇摩知識+如有不便請留言告知

最佳解答:

4x2 – 4xy + y2 – 2x + y = (4x2 – 4xy + y2) – (2x - y) = [(2x)2 – 2(2x)y + y2] – (2x - y) = (2x - y)2 – (2x - y) = (2x - y)(2x - y) – (2x - y) = (2x - y)(2x – y - 1) 9 – a2 + 3a – ab = (9 – a2) + a(3 - b) = (32 – a2) + a(3 - b) = (3 + a)(3 - a) + a(3 - b) 9 – b2 + 3a – ab = (9 – b2) + a(3 - b) = (32 – b2) + a(3 - b) = (3 + b)(3 - b) + a(3 - b) = (3 + a + b)(3 - b)

其他解答: