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F. 2 Method of Elimination
發問:
Solve by method of elimination. ?{(1/x)+(2/y)=(5/6)......(i) ?{(2/x)-(3/y)=(2/3)......(ii) Let a=(1/x), b=(1/y). From (i), a+2b=(5/6)......(iii) From (ii), 2a-3b=(2/3)......(iv) ...... Thanks.
(1/x) + (2/y) = (5/6) ...... (i) ?(2/x) - (3/y) = (2/3) ...... (ii) Let a = (1/x), b = (1/y). From (i): a + 2b = (5/6) ...... (iii) From (ii): 2a - 3b = (2/3) ...... (iv) (iii)*2: 2a + 4b = (5/3) ...... (v) (v) - (vi) 7b = 1 b = 1/7 Then y = 7 Put b = (1/7) into (iii): a + 2(1/7) = (5/6) a = (35/42) - (12/42) a = 23/42 Then x = 42/23 Ans: x = 42/23 and y = 7
其他解答:
F. 2 Method of Elimination
發問:
Solve by method of elimination. ?{(1/x)+(2/y)=(5/6)......(i) ?{(2/x)-(3/y)=(2/3)......(ii) Let a=(1/x), b=(1/y). From (i), a+2b=(5/6)......(iii) From (ii), 2a-3b=(2/3)......(iv) ...... Thanks.
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最佳解答:(1/x) + (2/y) = (5/6) ...... (i) ?(2/x) - (3/y) = (2/3) ...... (ii) Let a = (1/x), b = (1/y). From (i): a + 2b = (5/6) ...... (iii) From (ii): 2a - 3b = (2/3) ...... (iv) (iii)*2: 2a + 4b = (5/3) ...... (v) (v) - (vi) 7b = 1 b = 1/7 Then y = 7 Put b = (1/7) into (iii): a + 2(1/7) = (5/6) a = (35/42) - (12/42) a = 23/42 Then x = 42/23 Ans: x = 42/23 and y = 7
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