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標題:
KUMON MATHS I problem
發問:
X2+2x(y+z)+(y+z)2= X2-2x(y+z)+(y+z)2= X2+6x(a+b)+9(a+b)2= X2-6x(a+b)+9(a+b)2= X2-8x(x-3y)+16(x-3y)2= AND I 69A------I 70b answer 更新: factorise X2+2x(y+z)+(y+z)2= X2-2x(y+z)+(y+z)2= X2+6x(a+b)+9(a+b)2= X2-6x(a+b)+9(a+b)2= X2-8x(x-3y)+16(x-3y)2= 更新 2: 2(x+y)^2+5(x+y)+3= 2(x+y)^2+(x+y)-6= 2(x+y)^2-9(x+y)-5= 3(x+y)^2-13(x+y)+4= 2(x+y)^2+7x(x+y)+5x^2= 3(x-y)^2+2y(x-y)-5y^2= 7(x+y)^2+13y(x+y)-2y^2= x^2+5x(x+2y)+4(x+2y)^2= x^2+3x(x+3y)+2(x+3y)^2= x^2+5x(x+2y)+6(x+2y)^2= 3(x+2y)^2-13x(x+2y)+4x^2= 2(x+2y)^2+7x(x+2y)+5x^2= 3(2x-y)^2+2y(2x-y)-5y^2=
最佳解答:
X2+2x(y+z)+(y+z)2 x^2+2xy+yz+y^2+2yz+z^2x^2+2y3yz+y^2+z^2______________________X2-2x(y+z)+(y+z)2x^2-2xy-2xz+y^2+2yz+z^2 _____________________ X2+6x(a+b)+9(a+b)2 x^2+6ax+6bx+9(a^2+2ab+b^2) x^2+6ax+6bx+9a^2+18ab+9b^2 ________________________ X2-6x(a+b)+9(a+b)2 x^2-6ax-6x+9a^2+18ab+9b^2 ________________________ X2-8x(x-3y)+16(x-3y)2 x^2-8x^2+24xy+16(x^2-6xy+9y^2) 16+24xy-7x^2+16x^2+96xy+144y^2 16+120xy+9x^2+14y^2+24xy _________________________ 2010-07-16 12:16:52 補充： X2+2x(y+z)+(y+z)2 (x+y+z)^2 _________________ X2-2x(y+z)+(y+z)2 (x-y-z)^2 __________________ X2+6x(a+b)+9(a+b)2 (x^2+3a+3b)^2 ________________ X2-6x(a+b)+9(a+b)2 (x-3a-3b)^2 __________________ X2-8x(x-3y)+16(x-3y)2 (x-4x-12y)^2 _____________ 2010-07-16 13:42:17 補充： 2(x+y)^2+5(x+y)+3 (x+y+1)(2x+2y+3) 2010-07-16 13:43:12 補充： 2(x+y)^2+(x+y)-6 (2x+2y-3)(x+y+2) 2010-07-16 13:43:56 補充： 2(x+y)^2-9(x+y)-5 (x+y-5)(2x+2y+1) 2010-07-16 13:44:42 補充： 3(x+y)^2-13(x+y)+4 (3x+3y-1)(x+y-4) 2010-07-16 13:46:40 補充： 2(x+y)^2+7x(x+y)+5x^2 (2x+2y+5x)(x+y+x) (7x+2y)(2x+y) 2010-07-16 13:47:38 補充： 3(x-y)^2+2y(x-y)-5y^2 (3x-3y+5)(x-y-1) 2010-07-16 13:49:29 補充： 7(x+y)^2+13y(x+y)-2y^2 (7x+6y)(x+3y) 2010-07-16 13:51:11 補充： x^2+5x(x+2y)+4(x+2y)^2 (5x+2y)(2x+2y) 2(x+y)(5x+2y) 2010-07-16 13:52:50 補充： x^2+3x(x+3y)+2(x+3y)^2 (3x+6y)(2x+3y) 3(x+2y)(2x+3y) 2010-07-16 13:53:54 補充： x^2+5x(x+2y)+6(x+2y)^2 (4x+2y)(3x+2y) 2(2x+y)(3x+2y) 2010-07-16 13:56:02 補充： 3(x+2y)^2-13x(x+2y)+4x^2 (2x+2y)(2y-3x) 2(x+y)(2y-3x) 2010-07-16 13:57:27 補充： 2(x+2y)^2+7x(x+2y)+5x^2 (7x+2y)(2x+2y) 2(x+y)(7x+2y) 2010-07-16 13:59:55 補充： 3(2x-y)^2+2y(2x-y)-5y^2 (6x+2y)(2x-2y) 4(3x+y)(x-y) 2010-07-16 14:00:36 補充： 考試都冇甘難.............. 2010-07-16 15:09:56 補充： 有條錯左 ............... 2010-07-16 15:10:49 補充： 3(x-y)^2+2y(x-y)-5y^2 (3x-3y+5y)(x-y-y) (3x+2y)(x-2y)
其他解答:
KUMON MATHS I problem
發問:
X2+2x(y+z)+(y+z)2= X2-2x(y+z)+(y+z)2= X2+6x(a+b)+9(a+b)2= X2-6x(a+b)+9(a+b)2= X2-8x(x-3y)+16(x-3y)2= AND I 69A------I 70b answer 更新: factorise X2+2x(y+z)+(y+z)2= X2-2x(y+z)+(y+z)2= X2+6x(a+b)+9(a+b)2= X2-6x(a+b)+9(a+b)2= X2-8x(x-3y)+16(x-3y)2= 更新 2: 2(x+y)^2+5(x+y)+3= 2(x+y)^2+(x+y)-6= 2(x+y)^2-9(x+y)-5= 3(x+y)^2-13(x+y)+4= 2(x+y)^2+7x(x+y)+5x^2= 3(x-y)^2+2y(x-y)-5y^2= 7(x+y)^2+13y(x+y)-2y^2= x^2+5x(x+2y)+4(x+2y)^2= x^2+3x(x+3y)+2(x+3y)^2= x^2+5x(x+2y)+6(x+2y)^2= 3(x+2y)^2-13x(x+2y)+4x^2= 2(x+2y)^2+7x(x+2y)+5x^2= 3(2x-y)^2+2y(2x-y)-5y^2=
最佳解答:
X2+2x(y+z)+(y+z)2 x^2+2xy+yz+y^2+2yz+z^2x^2+2y3yz+y^2+z^2______________________X2-2x(y+z)+(y+z)2x^2-2xy-2xz+y^2+2yz+z^2 _____________________ X2+6x(a+b)+9(a+b)2 x^2+6ax+6bx+9(a^2+2ab+b^2) x^2+6ax+6bx+9a^2+18ab+9b^2 ________________________ X2-6x(a+b)+9(a+b)2 x^2-6ax-6x+9a^2+18ab+9b^2 ________________________ X2-8x(x-3y)+16(x-3y)2 x^2-8x^2+24xy+16(x^2-6xy+9y^2) 16+24xy-7x^2+16x^2+96xy+144y^2 16+120xy+9x^2+14y^2+24xy _________________________ 2010-07-16 12:16:52 補充： X2+2x(y+z)+(y+z)2 (x+y+z)^2 _________________ X2-2x(y+z)+(y+z)2 (x-y-z)^2 __________________ X2+6x(a+b)+9(a+b)2 (x^2+3a+3b)^2 ________________ X2-6x(a+b)+9(a+b)2 (x-3a-3b)^2 __________________ X2-8x(x-3y)+16(x-3y)2 (x-4x-12y)^2 _____________ 2010-07-16 13:42:17 補充： 2(x+y)^2+5(x+y)+3 (x+y+1)(2x+2y+3) 2010-07-16 13:43:12 補充： 2(x+y)^2+(x+y)-6 (2x+2y-3)(x+y+2) 2010-07-16 13:43:56 補充： 2(x+y)^2-9(x+y)-5 (x+y-5)(2x+2y+1) 2010-07-16 13:44:42 補充： 3(x+y)^2-13(x+y)+4 (3x+3y-1)(x+y-4) 2010-07-16 13:46:40 補充： 2(x+y)^2+7x(x+y)+5x^2 (2x+2y+5x)(x+y+x) (7x+2y)(2x+y) 2010-07-16 13:47:38 補充： 3(x-y)^2+2y(x-y)-5y^2 (3x-3y+5)(x-y-1) 2010-07-16 13:49:29 補充： 7(x+y)^2+13y(x+y)-2y^2 (7x+6y)(x+3y) 2010-07-16 13:51:11 補充： x^2+5x(x+2y)+4(x+2y)^2 (5x+2y)(2x+2y) 2(x+y)(5x+2y) 2010-07-16 13:52:50 補充： x^2+3x(x+3y)+2(x+3y)^2 (3x+6y)(2x+3y) 3(x+2y)(2x+3y) 2010-07-16 13:53:54 補充： x^2+5x(x+2y)+6(x+2y)^2 (4x+2y)(3x+2y) 2(2x+y)(3x+2y) 2010-07-16 13:56:02 補充： 3(x+2y)^2-13x(x+2y)+4x^2 (2x+2y)(2y-3x) 2(x+y)(2y-3x) 2010-07-16 13:57:27 補充： 2(x+2y)^2+7x(x+2y)+5x^2 (7x+2y)(2x+2y) 2(x+y)(7x+2y) 2010-07-16 13:59:55 補充： 3(2x-y)^2+2y(2x-y)-5y^2 (6x+2y)(2x-2y) 4(3x+y)(x-y) 2010-07-16 14:00:36 補充： 考試都冇甘難.............. 2010-07-16 15:09:56 補充： 有條錯左 ............... 2010-07-16 15:10:49 補充： 3(x-y)^2+2y(x-y)-5y^2 (3x-3y+5y)(x-y-y) (3x+2y)(x-2y)
其他解答:
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I think your expressions 'X2' and '(y+z)2' are representing square, therefore I hypothesise them as square. ( I don't think you want to express multiplying two) 1.x^2+2x(y+z)+(y+z)^2 =[x+(y+z)]^2 =(x+y+z)^2 Ans. 2.x^2-2x(y+z)+(y+z)^2 =[x-(y+z)]^2 =(x-y-z)^2 Ans. 3.x^2+6x(a+b)+9(a+b)^2 =[x+3(a+b)]^2 =(x+3a+3b)^2 Ans. 4.x^2-6x(a+b)+9(a+b)^2 =[x-3(a+b)]^2 =(x-3a-3b)^2 Ans. 5.x^2-8x(x-3y)+16(x-3y)^2 =[x-4(x-3y)]^2 =(x-4x+12y)^2 =(12y-3x)^2 =9(4y-x)^2 Ans. 6.2(x+y)^2+5(x+y)+3 =[2(x+y)+3][(x+y)+1] =(2x+2y+3)(x+y+1) Ans. 7.2(x+y)^2+(x+y)-6 =[2(x+y)-3][(x+y)+2] =(2x+2y-3)(x+y+2) Ans. 8.2(x+y)^2-9(x+y)-5 =[2(x+y)+1][(x+y)-5] =(2x+2y+1)(x+y-5) Ans. 9.3(x+y)^2-13(x+y)+4 =[3(x+y)-1][(x+y)-4] =(3x+3y-1)(x+y-4) Ans. 10.7(x+y)+13y(x+y)-2y^2 =[7(x+y)+y][(x+y)-2y] =(7x+7y+y)(x+y-2y) =(7x+8y)(x-y) Ans. 11.x^2+5x(x+2y)+4(x+2y)^2 =[x+(x+2y)][x+4(x+2y)] =(x+x+2y)(x+4x+8y) =2(x+y)(5x+8y) Ans. 12.x^2+3x(x+3y)+2(x+3y)^2 =[x+(x+3y)][x+2(x+3y)] =(2x+3y)(3x+6y) =3(2x+3y)(x+2y) Ans. 13.x^2+5x(x+2y)+6(x+2y)^2 =[x+2(x+2y)][x+3(x+2y)] =(3x+4y)(4x+6y) =2(3x+4y)(2x+3y) Ans. 14.3(x+2y)^2-13x(x+2y)+4x^2 =[3(x+2y)-x][(x+2y)-4x] =(2x+6y)(2y-3x) =2(x+3y)(2y-3x) Ans. 15.2(x+2y)^2+7x(x+2y)+5x^2 =[2(x+2y)+5x][(x+2y)+1] =(7x+4y)(x+2y+1) Ans. 16.3(2x-y)^2+2y(2x-y)-5y^2 =[3(2x-y)+5y][(2x-y)-1] =(6x+2y)(2x-y-1) =2(3x+y)(2x-y-1) Ans.|||||thankS!!!!!!
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