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標題:
form 4 maths
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最佳解答:
假設:S,T,U,V共線(colinear) STUV -+--+-+---+-(Not on scale,不按比例) Let ST = 6k <=[令下列的數值都成為整數] ST : TV = 2 : 5 6k : TV = 2 : 5 TV = 15k And SV = ST + TV = 6k + 15k = 21k As SU : SV = 2 : 3 SU : 21k = 2 : 3 SU = 14k On the other hand, SV = ST + TU + UV 21k = 6k + TU + 7k TU = 8k Therefore, SV : TU = 21k : 8k = 21 : 8 //
其他解答:
Actually there is no TU in your question, do u mean TV? if find SV:TU ST/TV=2/5 5ST=2TV SU/SV=2/3 2SV=3SU so, SV:TV =SV/TV =2SV/2V =3SU/5ST =3SU:5ST
form 4 maths
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ST : TV = 2 : 5 SU : SV = 2 : 3 find SV : TU.最佳解答:
假設:S,T,U,V共線(colinear) STUV -+--+-+---+-(Not on scale,不按比例) Let ST = 6k <=[令下列的數值都成為整數] ST : TV = 2 : 5 6k : TV = 2 : 5 TV = 15k And SV = ST + TV = 6k + 15k = 21k As SU : SV = 2 : 3 SU : 21k = 2 : 3 SU = 14k On the other hand, SV = ST + TU + UV 21k = 6k + TU + 7k TU = 8k Therefore, SV : TU = 21k : 8k = 21 : 8 //
其他解答:
Actually there is no TU in your question, do u mean TV? if find SV:TU ST/TV=2/5 5ST=2TV SU/SV=2/3 2SV=3SU so, SV:TV =SV/TV =2SV/2V =3SU/5ST =3SU:5ST
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