標題:
發問:
Factorise the following expression. [ Nos d~h]d. 4(m^4)e. 9 [ (1/m^2) + m + m^2]f. 108m^2 + 147g. [(m^2)+1 / m ] [(1-m^2) / m]h. (n^4 - 1) / (n^3 + n^2 + n + 1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~i. 根據以下 9a^2 - 6a + 1, 分解 (9x^2 - 18xy + 9y^2) - 6x +6y +1j. a^2 - 9b^2 = 36, (a/3) + b = 6.a-3b= ??k. [2/... 顯示更多 Factorise the following expression. [ Nos d~h] d. 4(m^4) e. 9 [ (1/m^2) + m + m^2] f. 108m^2 + 147 g. [(m^2)+1 / m ] [(1-m^2) / m] h. (n^4 - 1) / (n^3 + n^2 + n + 1) ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ i. 根據以下 9a^2 - 6a + 1, 分解 (9x^2 - 18xy + 9y^2) - 6x +6y +1 j. a^2 - 9b^2 = 36, (a/3) + b = 6. a-3b= ?? k. [2/ (x^2 + 4x +3 )] + [1/ (x^2 + 7x +12)]
最佳解答:
d. cannot be factorized. e. cannot be factorized. f. 3(36m^2 + 49) g. 1/(m^2) (m^3+1) (1-m^2) = 1/(m^2) (m+1)(m^2-m+1)(1+m)(1-m) = (m+1)^2/m^2 (1-m)(m^2-m+1) h. (n^4 - 1) / (n^3 + n^2 + n + 1) = (n-1)(n^3 + n^2 + n + 1)/(n^3 + n^2 + n + 1) = n - 1 i. 9a^2 - 6a + 1 = (3a - 1)^2 (9x^2 - 18xy + 9y^2) - 6x + 6y +1 = (3x - 3y) (3x - 3y) - 6x + 6y + 1 = (3x - 3y - 1) (3x - 3y - 1) = (3x - 3y - 1)^2 j. (a/3) + b = 6 a + 3b = 18 a^2 - 9b^2 = 36 (a + 3b) (a - 3b) = 36 18 (a - 3b) = 36 a - 3b = 2 k. [2/ (x^2 + 4x +3 )] + [1/ (x^2 + 7x +12)] = [2/ (x+1)(x+3)] + [1/ (x+3)(x+4)] = [2(x+4)/(x+1)(x+3)(x+4)] + [1(x+1)/(x+1)(x+3)(x+4)] = [(2x+8+x+1)/(x+1)(x+3)(x+4)] = [(3x+9)/(x+1)(x+3)(x+4)] = [3(x+3)/(x+1)(x+3)(x+4)] = 3/[(x+1)(x+4)]
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Form Three Maths Q.發問:
Factorise the following expression. [ Nos d~h]d. 4(m^4)e. 9 [ (1/m^2) + m + m^2]f. 108m^2 + 147g. [(m^2)+1 / m ] [(1-m^2) / m]h. (n^4 - 1) / (n^3 + n^2 + n + 1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~i. 根據以下 9a^2 - 6a + 1, 分解 (9x^2 - 18xy + 9y^2) - 6x +6y +1j. a^2 - 9b^2 = 36, (a/3) + b = 6.a-3b= ??k. [2/... 顯示更多 Factorise the following expression. [ Nos d~h] d. 4(m^4) e. 9 [ (1/m^2) + m + m^2] f. 108m^2 + 147 g. [(m^2)+1 / m ] [(1-m^2) / m] h. (n^4 - 1) / (n^3 + n^2 + n + 1) ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ i. 根據以下 9a^2 - 6a + 1, 分解 (9x^2 - 18xy + 9y^2) - 6x +6y +1 j. a^2 - 9b^2 = 36, (a/3) + b = 6. a-3b= ?? k. [2/ (x^2 + 4x +3 )] + [1/ (x^2 + 7x +12)]
最佳解答:
d. cannot be factorized. e. cannot be factorized. f. 3(36m^2 + 49) g. 1/(m^2) (m^3+1) (1-m^2) = 1/(m^2) (m+1)(m^2-m+1)(1+m)(1-m) = (m+1)^2/m^2 (1-m)(m^2-m+1) h. (n^4 - 1) / (n^3 + n^2 + n + 1) = (n-1)(n^3 + n^2 + n + 1)/(n^3 + n^2 + n + 1) = n - 1 i. 9a^2 - 6a + 1 = (3a - 1)^2 (9x^2 - 18xy + 9y^2) - 6x + 6y +1 = (3x - 3y) (3x - 3y) - 6x + 6y + 1 = (3x - 3y - 1) (3x - 3y - 1) = (3x - 3y - 1)^2 j. (a/3) + b = 6 a + 3b = 18 a^2 - 9b^2 = 36 (a + 3b) (a - 3b) = 36 18 (a - 3b) = 36 a - 3b = 2 k. [2/ (x^2 + 4x +3 )] + [1/ (x^2 + 7x +12)] = [2/ (x+1)(x+3)] + [1/ (x+3)(x+4)] = [2(x+4)/(x+1)(x+3)(x+4)] + [1(x+1)/(x+1)(x+3)(x+4)] = [(2x+8+x+1)/(x+1)(x+3)(x+4)] = [(3x+9)/(x+1)(x+3)(x+4)] = [3(x+3)/(x+1)(x+3)(x+4)] = 3/[(x+1)(x+4)]
其他解答:
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